為什么輸出一直是9，有大佬解決一下循環(huán)空運(yùn)行的問題么

#include <stdio.h>
int main()
{
??? int year = 2008;
??? int mouth = 8;
??? int day = 8;
??? int i=1;
??? int j;
??? for(i=12;i>=mouth;i--)
??? {
??? ?switch(i)
??{
???case1:
???break;
???case2:j=j+31;
???break;
???case3:j=j+28;
???break;
???case4:j=j+31;
???break;
???case5:j=j+30;
???break;
???case6:j=j+31;
???break;
???case7:j=j+30;
???break;
???case8:j=j+31;
???break;
???case9:j=j+31;
???break;
??}?
?}
??? if(year%400==0||year%4==0||year%100==0&&mouth>2)
??? {
??? ?day=day+1+j;
??? ?printf("%d",day);
?}
?else
?{
??day=day+j;
??printf("%d",day);
?}
??? return 0;
}

nog47

2019-02-12

源自：C語言入門 4-17

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3 回答

KingToAce
2019-02-14

#include?<stdio.h>
int?main()?
{?
????/*?定義需要計(jì)算的日期?*/
????int?year?=?2008;
????int?month?=?8;
????int?day?=?8;
????/*
?????*?請(qǐng)使用switch語句，if...else語句完成本題
?????*?如有想看小編思路的，可以點(diǎn)擊左側(cè)任務(wù)中的“不會(huì)了怎么辦”
?????*?小編還是希望大家獨(dú)立完成哦~
?????*/
????int?sumDay?=?0;
????for(int?i=1;i<month;i++){
????????switch(i){
????????????case?1:
????????????case?3:
????????????case?5:
????????????case?7:
????????????case?8:
????????????case?10:
????????????case?12:
????????????????sumDay+=31;
????????????????break;
????????????case?2:
????????????????if(year%4==0&&year%100!=0||year%400==0){
????????????????????sumDay+=29;
????????????????}else{
????????????????????sumDay+=28;
????????????????}
????????????????break;
????????????case?4:
????????????case?6:
????????????case?9:
????????????case?11:
????????????????sumDay+=30;
????????????????break;
????????}
????}
????sumDay+=day;
????printf("2008年8月8日是該年的第%d天",sumDay);
????return?0;
}