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長度10以內(nèi)的10個不同長度的字符串

package?src.com.cg;

import?java.util.*;

public?class?ListSort?{
????public?static?void?main(String[]?args)?{
????????//定義一個字符串包含?數(shù)字和字母
????????String?str?=?"zxcvbnmlkjhgfdsaqwertyuiopQWERTYUIOPASDFGHJKLZXCVBNM1234567890";
????????List<String>?list?=?new?ArrayList<>();
????????ListSort?sort?=?new?ListSort();
????????//添加元素
????????sort.add(str,?list);
????????System.out.println(list.size());
????????for?(String?s?:?list)?{
????????????System.out.println("排序前的字符串是"?+?s);
????????}
????????Collections.sort(list,?new?Comparator<String>()?{
????????????@Override
????????????public?int?compare(String?o1,?String?o2)?{
????????????????return?o1.length()?-?o2.length();
????????????}
????????});
????????for?(String?s?:?list)?{
????????????System.out.println("排序后的字符串是:"?+?s);
????????}
????}


????private?void?add(String?str,?List<String>?list)?{
????????Random?random?=?new?Random();
????????do?{
????????????StringBuilder?sb?=?new?StringBuilder();
????????????//?隨機生生成一個10以內(nèi)的長度
????????????int?i?=?random.nextInt(11);
????????????//用這個長度去循環(huán)遍歷生成該長度的字符串
????????????for?(int?i1?=?0;?i1?<?i;?i1++)?{
????????????????int?i2?=?random.nextInt(62);
????????????????sb.append(str.charAt(i2));
????????????}
????????????//過濾掉空字符串和重復的字符串
????????????if?(!sb.toString().isEmpty()?&&?(!list.contains(sb.toString())))?{
????????????????//保證每個元素的長度都是不一樣的
????????????????if?(list.isEmpty())?{
????????????????????list.add(sb.toString());
????????????????}?else?{
????????????????????boolean?flag?=?false;
????????????????????for?(int?i4?=?0,?length?=?list.size();?i4?<?length;?i4++)?{
????????????????????????if?((list.get(i4).length()?==?sb.length()))?{
????????????????????????????flag?=?true;
????????????????????????}
????????????????????}
????????????????????if?(!flag)?{
????????????????????????list.add(sb.toString());
????????????????????}
????????????????}
????????????}
????????}?while?(list.size()?!=?10);

????}


}


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2 回答

public void testSort4() {

List<String> stringList = new ArrayList<String>();

Random random = new Random();

char[] charList = {'a','b','c','d','e','f','d','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};


String string = "";

for(int i = 0 ; i <10 ; ++i) {

int bit = random.nextInt(10) + 1;

do {

string = "";

for(int j = 0 ; j <bit ; ++j) {

string += charList[random.nextInt(26)];

}

}while(stringList.contains(string));

stringList.add(string);

}


System.out.println("--------------排序前---------------");

for (String str : stringList) {

System.out.println("字母:" + str);

}

Collections.sort(stringList);

System.out.println("--------------排序后---------------");

for (String str : stringList) {

System.out.println("字母:" + str);

}

}


0 回復 有任何疑惑可以回復我~

package com.imooc.collection;


import java.util.ArrayList;

import java.util.Collections;

import java.util.Iterator;

import java.util.List;

import java.util.Random;


public class CollectionsTest {

/**

* 泛型為Integer的List排序

* @param args

*/

public void testSort1(){

List<Integer> list = new ArrayList<Integer>();

Random random = new Random();

int k;

for(int i=0;i<10;i++){

do{

k = random.nextInt(100);

}while(list.contains( k));

list.add(k);

System.out.println("隨機數(shù):"+k);

}

//排序前遍歷隨機數(shù)

System.out.println("--------排序前遍歷隨機數(shù)------");

for (Integer integer : list) {

System.out.println("隨機數(shù):"+integer);

}

//集合排序

Collections.sort(list);

//排序后遍歷隨機數(shù)

System.out.println("--------排序后遍歷隨機數(shù)------");

Iterator<Integer> iterator = list.iterator();

while(iterator.hasNext()){

System.out.println("隨機數(shù):"+iterator.next());

}

}

/**

* 泛型為字符串的排序

* @param args

*/

public void testSort2(){

ArrayList<String> listStr = new ArrayList<String>();

listStr.add("jenny");

listStr.add("Mark");

listStr.add("tom");

System.out.println("--------排序前遍歷字符串------");

for (String string : listStr) {

System.out.println("字符串:"+string);

}

Collections.sort(listStr);

System.out.println("--------排序后遍歷字符串------");

for (String string : listStr) {

System.out.println("字符串:"+string);

}

}

/**

* 是個字符串,長度是1-10

* @param args

*/

public void testSort3(){

List<String> list = new ArrayList<String>();

Random random = new Random();

String use = "0123456789asdfghjklzxcvbnmqwertyuiopASDFGHJKLQWERTYUIOPXZCVBNM";

char[] charArray = use.toCharArray();

int b = charArray.length;

int k;

int index;

String bb="";

for(int i=0;i<10;i++){

do{

k = random.nextInt(10);

for(int j=0;j<=k;j++){

?index = random.nextInt(charArray.length);

?char c = charArray[index];

?bb+=c;

}

}while(list.contains(bb));

list.add(bb);

System.out.println("隨機字符串:"+bb);


bb="";

}

System.out.println("----------排序前遍歷字符串---------");

for (String str : list) {

System.out.println("隨機字符串:"+str);

}

System.out.println("----------排序后遍歷字符串---------");

Collections.sort(list);

for (String str : list) {

System.out.println("隨機字符串:"+str);

}

}


public static void main(String[] args) {

// TODO Auto-generated method stub

CollectionsTest collectionsTest = new CollectionsTest();

//collectionsTest.testSort1();

//collectionsTest.testSort2();

collectionsTest.testSort3();

}


}


0 回復 有任何疑惑可以回復我~

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長度10以內(nèi)的10個不同長度的字符串

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