求 個(gè)位大神幫幫忙看看哪錯(cuò)了。
#include <stdio.h>
int main()
{
??? int score[10]={67,98,75,63,82,79,81,91,66,84};
??? int sum=0;
??? int n;
??? for(n =0;n <= 10;n++)
??? {
??????? sum += score[n];
??? }
??? printf("考試總分是%d\n",sum);
??? int max=score[0];
??? for(n=0;n<10;n++)
??? {
??????? if(max<score[n])
??????? {
??????????? max=score[n];?? ?
??????? }
??? }
??? printf("最高分是%d\n",max);
??? int min=score[0];
??? for(n=0;n<10;n++)
??? {
??????? if(min>score[n])
??????? {
??????????? min=score[n];?? ?
??????? }
??? }
??? printf("最低分是%d\n",min);
??? float adv;
??? for(n =0;n <= 10;n++)
??? {
??????? sum += score[n];
??????? adv = sum*1.0/10;
??? }
??? printf("平均分是%f\n",adv);
?? ?return 0;
}
2019-02-01
求和的時(shí)候就出錯(cuò)了: for(n =0;n <= 10;n++),如果<=10的話會(huì)出現(xiàn)score[10]這個(gè)不存在的數(shù)據(jù),系統(tǒng)就隨機(jī)分配一個(gè)數(shù)據(jù)給這個(gè)值,所以應(yīng)該改為<=9;
然后求平均值的時(shí)候sum沒有初始化,還是會(huì)帶入求和的時(shí)候的值,及真正的sum,應(yīng)該重新定義一下,讓sum=0.
2018-12-15
adv這一行,挪到for循環(huán)外`~