為什么運行成功,輸出錯誤 2008年8月8日這一天,是該年中的第809337664天
#include <stdio.h>
int main()
{
??? /* 定義需要計算的日期 */
??? int year = 2008;
??? int month = 8;
??? int day = 8;
??? /*
???? * 請使用switch語句,if...else語句完成本題
???? * 如有想看小編思路的,可以點擊左側(cè)任務中的“不會了怎么辦”
???? * 小編還是希望大家獨立完成哦~
???? */
??? int sum,feb;
??? if(year%4==0&&year%100!=0||year%400==0)
??? {
??????? feb=29;
??? }???
??? else
??? {
??????? feb=28;
??? }???
??? int jan,mar,may,jul,aug,oct=31;
??? int apr,jun,sep,nov=30;
??? switch(month)
??? {
??????? case 1:
??????? sum=day;
??????? break;
??????? case 2:
??????? sum=day+jan;
??????? break;
??????? case 3:
??????? sum=day+jan+feb;
??????? break;
??????? case 4:
??????? sum=day+jan+feb+mar;
??????? break;
??????? case 5:
??????? sum=day+jan+feb+mar+apr;
??????? break;
??????? case 6:
??????? sum=day+jan+feb+mar+apr+may;
??????? break;
??????? case 7:
??????? sum=day+jan+feb+mar+apr+may+jun;
??????? break;
??????? case 8:
??????? sum=day+jan+feb+mar+apr+may+jun+jul;
??????? break;
??????? case 9:
??????? sum=day+jan+feb+mar+apr+may+jun+jul+aug;
??????? break;
??????? case 10:
??????? sum=day+jan+feb+mar+apr+may+jun+jul+aug+sep;
??????? break;
??????? case 11:
??????? sum=day+jan+feb+mar+apr+may+jun+jul+aug+sep+oct;
??????? break;
??????? case 12:
??????? sum=day+jan+feb+mar+apr+may+jun+jul+aug+sep+oct+nov;
??????? break;
??????? default:printf("一年當中只有12個月哦~");
??????? break;
??? }
??? printf("%d年%d月%d日這一天,是該年中的第%d天",year,month,day,sum);
?return 0;
}
2018-09-11
? ? int jan,mar,may,jul,aug,oct=31;
??? int apr,jun,sep,nov=30;這兩句錯了,每個月都需要單獨賦值。