算出來剛好比答案多31天,可case1 時不就是有31 天馬
#include <stdio.h>
int main()
{
??? int year = 2008;
??? int month = 8;
??? int day =8;
??? int sum,i;
??? if((year%4==0&&year%100!=0)||year%400==0)
?? {
??? i=29;
?? }
??? else
??? {
??? i=28;
??? }
???
??? switch(month)
{
??? case 1:sum=31;break;
??? case 2:sum=31+i;break;
??? case 3:sum=31+i+31;break;
??? case 4:sum=31+i+31+30;break;
??? case 5:sum=31+i+31+30+31;break;
se 11:sum=31+i+31+30+31+30+31+31+30+31+30;break;
??? case 12:sum=31+i+31+30+31+30+31+31+30+31+30+31;break;
}
??? sum+=day;
printf("%d年%d月%d日是該年的第%d天",year,month,day,sum);
??? return 0;
}
???
??????? case 6:sum=31+i+31+30+31+30;break;
??? case 7:sum=31+i+31+30+31+30+31;break;
??? case 8:sum=31+i+31+30+31+30+31+31;break;
??? case 9:sum=31+i+31+30+31+30+31+31+30;break;
??? case 10:sum=31+i+31+30+31+30+31+31+30+31;break;
??? ca
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???
???
???
2018-09-03
1月的時候不能算31天,比如他問你2008年1月8號是第幾天的話,應該是第8天,過完1月到2月才能加31
2018-09-14
8月份 只能加 8天
2018-09-01
#include <stdio.h>
int main()
{
??? int year = 2008;
??? int month = 8;
??? int day =8;
??? int sum,i;
??? if((year%4==0&&year%100!=0)||year%400==0)
?? {
??? i=29;
?? }
??? else
??? {
??? i=28;
??? }
???
??? switch(month)
{
??? case 1:sum=31;break;
??? case 2:sum=31+i;break;
??? case 3:sum=31+i+31;break;
??? case 4:sum=31+i+31+30;break;
??? case 5:sum=31+i+31+30+31;break;
?case 6:sum=31+i+31+30+31+30;break;
? ?? case 7:sum=31+i+31+30+31+30+31;break;
??? case 8:sum=31+i+31+30+31+30+31+31;break;
??? case 9:sum=31+i+31+30+31+30+31+31+30;break;
??? case 10:sum=31+i+31+30+31+30+31+31+30+31;break;
??? case 11:sum=31+i+31+30+31+30+31+31+30+31+30;break;
??? case 12:sum=31+i+31+30+31+30+31+31+30+31+30+31;break;
}
??? sum+=day;
printf("%d年%d月%d日是該年的第%d天",year,month,day,sum);
??? return 0;
}
? ??
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