為什么在int b哪里直接聲明int b=in.read()后輸出的數(shù)據(jù)未能進(jìn)行進(jìn)制轉(zhuǎn)化?會(huì)連續(xù)出現(xiàn) 49 49 49 49不停止,而老師先聲明b然后在while循環(huán)里賦上in.read()輸出的字節(jié)碼卻沒(méi)問(wèn)題呢?
我所敲的不能進(jìn)行轉(zhuǎn)化，連續(xù)輸出49……的代碼:
FileInputStream in = new FileInputStream(fileName);
int b=in.read();
int i = 0;
while (b ?!= -1) {
System.out.print(Integer.toHexString(b) + " ");
while (i++ % 10 == 0)
System.out.println();
}
in.close();
老師敲的沒(méi)問(wèn)題的代碼:
FileInputStream in = new FileInputStream(fileName);
int b;
int i = 0;
while ((b = in.read()) != -1) {
System.out.print(Integer.toHexString(b) + " ");
while (i++ % 10 == 0)
System.out.println();
}
in.close();
2017-11-26
因?yàn)槟氵@個(gè)代碼只在聲明的時(shí)候讀取了一次，老師的放在while循環(huán)里每次進(jìn)行循環(huán)都會(huì)讀取一次。