自動(dòng)生成的xml mapping file會(huì)根據(jù)Student.java和Address.java分別生成兩個(gè)mapping file，然后在Student的mapping文件中有一個(gè)many-to-one的屬性。代碼如下：

<?xml?version="1.0"?>
<!DOCTYPE?hibernate-mapping?PUBLIC?"-//Hibernate/Hibernate?Mapping?DTD?3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!--?Generated?2017-8-24?15:05:51?by?Hibernate?Tools?3.5.0.Final?-->
<hibernate-mapping>
????<class?name="hibernate.model.component.Address"?table="ADDRESS">
????????<id?name="postcode"?type="java.lang.String">
????????????<column?name="POSTCODE"?/>
????????????<generator?class="assigned"?/>
????????</id>
????????<property?name="phone"?type="java.lang.String">
????????????<column?name="PHONE"?/>
????????</property>
????????<property?name="address"?type="java.lang.String">
????????????<column?name="ADDRESS"?/>
????????</property>
????</class>
</hibernate-mapping>

<?xml?version="1.0"?>
<!DOCTYPE?hibernate-mapping?PUBLIC?"-//Hibernate/Hibernate?Mapping?DTD?3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!--?Generated?2017-8-24?15:05:51?by?Hibernate?Tools?3.5.0.Final?-->
<hibernate-mapping>
????<class?name="hibernate.model.Student"?table="STUDENT">
????????<id?name="sid"?type="int">
????????????<column?name="SID"?/>
????????????<generator?class="assigned"?/>
????????</id>
????????<property?name="sname"?type="java.lang.String">
????????????<column?name="SNAME"?/>
????????</property>
????????<property?name="gender"?type="java.lang.String">
????????????<column?name="GENDER"?/>
????????</property>
????????<property?name="birthday"?type="java.util.Date">
????????????<column?name="BIRTHDAY"?/>
????????</property>
????????<many-to-one?name="address"?class="hibernate.model.component.Address"?fetch="join">
????????????<column?name="ADDRESS"?/>
????????</many-to-one>
????????<property?name="picture"?type="java.sql.Blob">
????????????<column?name="PICTURE"?/>
????????</property>
????</class>
</hibernate-mapping>