與，或運(yùn)算
x=2,y=3,z=4,
((x+y)>z)&&(y==z)&&x||y+z&&y+z
慕粉222048329
2017-06-12
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2017-06-12
#include <stdio.h>?
int main() {?
?int x = 2,y = 3,z = 4;
?printf("%c\n",((x+y)>z)&&(y==z)&&x||y+z&&y+z?'y':'n');
?return 0;?
}
2017-06-12
#include?<stdio.h>? int?main()?{? ????int?x?=?2,y?=?3,z?=?4; ????if(((x+y)>z)&&(y==z)&&x||y+z&&y+z) ?????printf("true"); ????eles ????printf("false")? ????return?0;? }