public?void?kindChoice?(int?num)?throws?NameNoMatchException{
		switch?(num)?{
		case?1:
			System.out.println("請輸入圖書名稱：");
			String?name?=?(String)new?Scanner(System.in).nextLine().toString();
			try?{
				nameChoice(name);
			}?catch?(NameNoMatchException?e)?{
				System.out.println("輸入的圖書名字不存在");
				//回滾操作
				orderChoice();	
			}
			break;
		case?2:
			System.out.println("請輸入圖書序號：");
			int?bookNum?=?new?Scanner(System.in).nextInt();
			try?{
				numChoice(bookNum);
			}?catch?(NameNoMatchException?e)?{
				System.out.println("輸入的圖書序號不存在");
				orderChoice();
			}
			break;
		default:
			throw?new?NameNoMatchException("命令輸入錯(cuò)誤，請根據(jù)提示重新輸入");
		}
	}

重新截了一下kindChoice方法 這樣好看點(diǎn)

public?void?nameChoice(String?name)?throws?NameNoMatchException?{
		
		String[]?books?=?{"xiyouji"?,?"hongloumeng"?,?"zhuxian"?,?"guichuideng"};
		boolean?isFind?=?false;
		for?(String?bookName?:?books)?{
			if?(bookName.equals(name))?{
				System.out.println("book:"?+?name);
				isFind?=?true;
				break;
			}
		}
		if?(!isFind)?{
			throw?new?NameNoMatchException();
		}
	}

public void kindChoice (int num) throws NameNoMatchException{

switch (num) {

case 1:

System.out.println("請輸入圖書名稱：");

String name = (String)new Scanner(System.in).nextLine().toString();

try {

nameChoice(name);

} catch (NameNoMatchException e) {

System.out.println("輸入的圖書名字不存在");

//回滾操作

orderChoice();

}

break;

case 2:

System.out.println("請輸入圖書序號：");

int bookNum = new Scanner(System.in).nextInt();

try {

numChoice(bookNum);

} catch (NameNoMatchException e) {

System.out.println("輸入的圖書序號不存在");

orderChoice();

}

break;

default:

throw new NameNoMatchException("命令輸入錯(cuò)誤，請根據(jù)提示重新輸入");

}

}

在kindChoice方法中獲取的控制臺輸入 漢字比較總是出錯(cuò)

代碼貼出來吧~

這樣試了還是不行 書名是從控制臺通過scanner獲取的

for(int i=0;i<arr.length;i++){

????str.equals(arr[i]);

}