……又求改
能幫我找出哪里出錯(cuò)了嗎？
?int?num?=?999;
int?count?=?0;
if?(o<=num<=999999999){
????count=count++;
????for(;;count++){
????????if((num-Math.pow(10,count))<0)
????????continue;
????}
}else{
????System.out.println("數(shù)據(jù)不符合判斷條件！")
}
System.out.println("它是個(gè)"+count+"位的數(shù)！")
}
}
2016-12-05
接上
package com.xuexi;
import java.lang.Math;
public class ShiYan{
public static void main(String args[]){
int num = 999;
int count = 0;
if (num>=0&&num<=999999999){//這不能這么寫(xiě)應(yīng)該是num>=xx&&num<=xx
? ?//count=count++;沒(méi)有用在這里
? ?for(;;count++){
? ? ? ?if((num-Math.pow(10,count))<0){
? ? ? ? break;
? ? ? ?}
? ? ? ? ??
? ?}
}else{
? ?System.out.println("數(shù)據(jù)不符合判斷條件！");//這少分號(hào)
}
System.out.println("它是個(gè)"+count+"位的數(shù)！");//這少分號(hào)
}
}
運(yùn)行結(jié)果:它是個(gè)3位的數(shù)！
2016-12-05
輸出的地方少兩個(gè)分號(hào);if循環(huán)不能那么寫(xiě).
用&&連接.
2016-12-05
package?javalx.com; ? ?public?class?Lx03 ????{ ??????public?static?void?main(String[]?args)?{ int?num?=?999; ????????int?count?=?0; ????{ if?(num?>=0?&&?num?<=999999999){ ????count=count++; ????for(;;count++){ ????????if((num-Math.pow(10,count))<0) ????????continue; ????} } ????else ????{ ?????System.out.println("數(shù)據(jù)不符合判斷條件！"); ????} ????System.out.println("它是個(gè)"+count+"位的數(shù)！"); ????} ???} } //雖然沒(méi)報(bào)錯(cuò)，但好像還是有點(diǎn)問(wèn)題2016-12-05
public static void main(String[] args){
int num = 999;
int count = 0;
if(num >=0 && num <=999999999) {
? ? while(num != 0) {
? ? ? ? count++;
? ? ? ? num /=10;
? ? }
? ? System.out.println("它是個(gè)"+count + "位的數(shù)！");
} else {
? ? System.out.println("輸入有誤!");
}
2016-12-05
buzhidao a