為什么校驗不通過也可以提交
我按照老師說的那么寫了之后 但是校驗不通過也可以提交數(shù)據(jù)給后臺???那這樣怎么行呢
?$("#signup").validate({ ????????rules:{ ????????????Username:{ ????????????????required:true, ????????????????minlength:2 ????????????}, ????????????EmailAddress:{ ????????????????required:true, ????????????????email:true ????????????}, ????????????Password:{ ????????????????required:true, ????????????????minlength:?6, ????????????????maxlength:?18 ????????????} ????????}, ????????messages:?{ ????????????Username:?{ ????????????????required:"請輸入用戶名", ????????????????minlength:"至少兩位" ????????????}, ????????????EmailAddress:?{ ????????????????required:"請輸入密碼", ????????????????email:"郵箱格式不對" ????????????}, ????????????Password:{ ????????????????required:true, ????????????????minlength:?"最少六位", ????????????????maxlength:?"最多18位" ????????????} ????????}, ????????submitHandler:?function?(form)?{?//?for?demo ????????????alert('valid?form?submitted');?//?for?demo ????????????$("input[id=submit2]").click(function?()?{ ????????????????event.preventDefault(); ????????????????$.post("http://218.192.169.173/taobao/login.php",?{ ????????????????????email:?$("#EmailAddress1").val(), ????????????????????password:?$("#PassWord").val() ????????????????},?function?(data,?textStatus)?{ ????????????????????var?username?=?data.username; ????????????????????var?errnum?=?data.errno; ????????????????????alert(username); ????????????????},"json"); ????????????}); ????????????return?false;?//?for?demo ????????} }) });
這是我的js代碼
2016-11-18
會不會是提交按鈕(submit2)本身的設(shè)置,比如類型就是submit?