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為什么這個(gè)newDefer直接用了,前面也沒(méi)有定義???

then:?function(?/*?fnDone,?fnFail,?fnProgress?*/?)?{
????????????????????var?fns?=?arguments;
????????????????????return?jQuery.Deferred(function(?newDefer?)?{????
//--------------?newDefer?也為什么直接就有了resolve,done方法呢???????????????
????????????????????
????????????????????????jQuery.each(?tuples,?function(?i,?tuple?)?{
????????????????????????????var?action?=?tuple[?0?],
????????????????????????????????fn?=?jQuery.isFunction(?fns[?i?]?)?&&?fns[?i?];
????????????????????????????//?deferred[?done?|?fail?|?progress?]?for?forwarding?actions?to?newDefer
????????????????????????????deferred[?tuple[1]?](function()?{
????????????????????????????????var?returned?=?fn?&&?fn.apply(?this,?arguments?);
????????????????????????????????if?(?returned?&&?jQuery.isFunction(?returned.promise?)?)?{
????????????????????????????????????returned.promise()
????????????????????????????????????????.done(?newDefer.resolve?)
????????????????????????????????????????.fail(?newDefer.reject?)
????????????????????????????????????????.progress(?newDefer.notify?);
????????????????????????????????}?else?{
????????????????????????????????????newDefer[?action?+?"With"?](?this?===?promise???newDefer.promise()?:?this,?fn???[?returned?]?:?arguments?);
????????????????????????????????}
????????????????????????????});
????????????????????????});
????????????????????????fns?=?null;
????????????????????}).promise();
????????????????}


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1 回答

懂了,汗,自己突然就想通了,原因在于這行代碼:

if?(?func?)?{
????????????func.call(?deferred,?deferred?);
????????}

call里面第二個(gè)deferred對(duì)象作為參數(shù)穿進(jìn)去了,正好對(duì)應(yīng)

?return?jQuery.Deferred(function(?newDefer?)?{

這個(gè)newDefer, 這樣就對(duì)啦,哈哈

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為什么這個(gè)newDefer直接用了,前面也沒(méi)有定義啊?

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