求解-來個(gè)老師幫忙看看
第五行沒錯(cuò)啊
<?php
$num_float1 = 1.234;
echo $num_float1;
echo "<br />";
$unm_float2 = 1.2e3;
echo $num_float2;
echo "<br />";
$unm_float3 = 1.2e-1;
echo $num_float3;
echo "<br />";
?>
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第五行沒錯(cuò)啊
<?php
$num_float1 = 1.234;
echo $num_float1;
echo "<br />";
$unm_float2 = 1.2e3;
echo $num_float2;
echo "<br />";
$unm_float3 = 1.2e-1;
echo $num_float3;
echo "<br />";
?>
2016-04-25
舉報(bào)
2017-08-18
定義的變量和輸出的不是一個(gè)東西
2016-10-25
是$num_float2而不是$unm_float2；
2016-05-12
<?php
$num_float1 = 1.234;
echo $num_float1;
echo "<br />";
$num_float2 = 1.2e3; ? ??
echo $num_float2;
echo "<br />";
$unm_float3 = 7.0E-1;
echo $num_float3;
echo "<br />";
?>
2016-04-25
你把變量名寫成$unm_float2,$unm_float3了
2016-04-25
變量名是$num_float2,$num_float3