我的答案是69.400002，求大神忙我看看

#include?<stdio.h>

float?str(i,j)
{
????float?n;
????if(i<=3)
????n=14;
????else?if(j>=23||j<=5)
????n=14+(i-3)*2.3*1.2;
????else
????n=14+(i-3)*2.3;
????return?n;
????}
int?main()
{
????printf("小明每天打車費用為%f",str(12,9)+str(12,18));
????return?0;
}

Wangyj1108

2016-04-01

源自：C語言入門 5-14

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2 回答

屎大彪回答被采納 +3 積分
2016-04-01

#include <stdio.h>
double getTaxiPrice(int hours,int distance)
{
?double totalPrice = 0.0;?//定義打車費用
?double perPrice = 2.3;?//定義每公里單價計費
?int startPrice = 13;?//定義起步價

?if(hours<0 || hours>24){
??printf("請?zhí)顚懻_的時間\n");
??return 0;
?}
?else if(!(hours>=5 && hours<23))?//判斷打車時間是否要增加費用
?{
??perPrice *= 1.2;?//費用增加20%????????????????????????
?}
?if(distance >3)??//判斷公里數(shù)
?{
??totalPrice = startPrice +(distance - 3)*perPrice;?//計算價錢
?}
?else
?{
??totalPrice = startPrice;???
?}
?totalPrice++;?//加一塊錢的燃油費
?return totalPrice;
}
int main()
{
?int moring = 9;?//定義上午打車時間
?int afternoon = 18;?//定義下午打車時間
?int distance = 12;?//定義打車公里數(shù)
?double totalPrice = 0;?//定義總費用
?if(getTaxiPrice(moring,distance) != 0)
?{
??totalPrice = getTaxiPrice(moring,distance);?//調(diào)用計算費用的函數(shù)
?}
?else if(totalPrice != 0)
?{
??totalPrice += getTaxiPrice(afternoon,distance);?//調(diào)用計算費用的函數(shù)
?}
?printf("小明每天打車的總費用是：%.2f\n",totalPrice);?//輸出
?return 0;???
}