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七巧板的問題

<!DOCTYPE html>

<html>

<head>

<meta charset="UTF-8">

<title>七巧板的實(shí)現(xiàn)</title>

</head>

<body>

<script type="text/javascript">

var tangram = [

{p:[{x:0,y:0},{x:800,y:0},{x:400,y:400}],color:"#caff67"},

{p:[{x:0,y:0},{x:400,y:400},{x:0,y:800}],color:"#67becf"},

{p:[{x:800,y:0},{x:800,y:400},{x:600,y:600},{x:600,y:200}],color:"#ef3d61"},

{p:[{x:600,y:200},{x:600,y:600},{x:400,y:400}],color:"#f9f51a"},

{p:[{x:400,y:400},{x:600,y:600},{x:400,y:800},{x:200,y:600}],color:"#a594c0"},

{p:[{x:200,y:600},{x:400,y:800},{x:0,y:800}],color:"#fa8ecc"},

{p:[{x:800,y:400},{x:800,y:800},{x:400,y:800}],color:"#f6ca29"}

];


window.onload = function(){

var canvas = document.getElementById('canvas');

canvas.width = 800;

canvas.height = 800;

var context = canvas.getContext('2d');

for (var i=0;i<tangram.length;i++) {

draw(tangram[i],context);

}

}

function draw(piece,cxt) {

cxt.beginPath();

cxt.moveTo(piece.p[0].x,piece.p[0].y);

for (var i=1;i<piece.length;i++) {

cxt.lineTo(piece.p[i].x,piece.p[i].y);

}

cxt.closePath();

cxt.fillStyle = piece.color;

cxt.fill();

}

</script>

<canvas id="canvas"></canvas>

</body>

</html>

自己到底哪里錯(cuò)了?

正在回答

2 回答

for (var i=1;i<piece.p.length;i++) {

cxt.lineTo(piece.p[i].x,piece.p[i].y);

}?

應(yīng)該是piece對(duì)象的p屬性的長度


0 回復(fù) 有任何疑惑可以回復(fù)我~
#1

飛飛赫赫 提問者

非常感謝!
2016-04-04 回復(fù) 有任何疑惑可以回復(fù)我~

function draw(piece,cxt){
? ?cxt.beginPath();
? ?cxt.moveTo(piece.p[0].x,piece.p[0].y);
? ?for(var i = 0;i<piece.p.length;i++){
? ? ? ?cxt.lineTo(piece.p[i].x,piece.p[i].y);

? ?}
? ?cxt.closePath();
? ?cxt.fillStyle = piece.color;
? ?cxt.fill();

? ?cxt.strokeStyle = "black";
? ?cxt.stroke();
}


第2個(gè)for循環(huán)里,索引應(yīng)該是var i = 0;

0 回復(fù) 有任何疑惑可以回復(fù)我~

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