如果公式判斷小于0，我們應(yīng)該返回什么呢？
import math
def quadratic_equation(a, b, c):
??? t=math.sqrt(b*b-4*a*c)
??? if t>=0:
??????? return (-b+t)/(2*a),(-b-t)/(2*a)
??? else:
??????? return 0
print quadratic_equation(2, 3, 0)
print quadratic_equation(1, -6, 5)
qq_初妝_0
2016-03-14
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2016-03-14
# -*- coding: utf-8 -*-
import math
def quadratic_equation(a, b, c):
??? t=math.sqrt(b*b-4*a*c)
??? if t>=0:
??????? return (-b+t)/(2*a),(-b-t)/(2*a)
??? else:
? ? ? ? print u“無解”
??????? return?
print quadratic_equation(2, 3, 0)
print quadratic_equation(1, -6, 5)
2016-05-05
參考答案應(yīng)該考慮deta<0的情況，