各位大神！求助，任務(wù)是判斷一個(gè)數(shù)（小于10位）的位數(shù)，輸入999，則輸出“它是個(gè)3位的數(shù)”
public class HelloWorld{
public static void main(String[] args){
int num = 999;
int count = 0;
if(num>=100&&num<=999)
{
? ? System.out.println("它是個(gè)3位的數(shù)")；
}else if (num>=10&&num<=99){
? ? "他是兩位數(shù)"
}
}
}
2016-02-27
import?java.util.Scanner; public?class?test?{ public?static?void?main(String[]?args){ Scanner?input?=?new?Scanner(System.in); System.out.print("請(qǐng)輸入:"); int?number?=?input.nextInt(); int?count?=?0; if(number?==?0){ System.out.println("它是個(gè)1位的數(shù)"); }else{ while(number?!=?0){ number?/=?10; count++; } System.out.println("它是個(gè)"+count+"位的數(shù)"); } } }2016-02-27
if (num >= 0 ?&& num<=999999999){
while(num != 0){
count++;
num/=10;
}
System.out.println("它是個(gè)"+ count+"位的數(shù)！");
} else{
System.out.println("輸入有誤！");
}