如果生成的含有中文驗(yàn)證碼的圖片亂碼需要按以下方式修改嗎？還是只要添加幾行代碼修改一下就行？

1. 確認(rèn)%JavaHome%/jre/lib/fonts目錄下存在zysong.ttf，如果不存在，可以將windows下的C:\WINDOWS\Fonts\simsun.ttc復(fù)制到此目錄，然后改名為zysong.ttf。
   2.在%JavaHome%/jre/lib/fonts目錄下執(zhí)行"ttmkfdir -o fonts.dir"命令,重新生成fonts.dir文件，如沒有此命令，請執(zhí)行：sudo apt-get install ttmkfdir。
   3.確認(rèn)/usr/share/fonts/zh_CN/TrueType目錄存在,如果不存在則mkdir創(chuàng)建
   4.確認(rèn)/usr/share/fonts/zh_CN/TrueType目錄下存在zysong.ttf
   5.在%JavaHome%/jre/lib目錄下,執(zhí)行 cp fontconfig.RedHat.3.properties.src fontconfig.properties
   6.重新啟動tomcat

   

   其實(shí)圖片上應(yīng)為“網(wǎng)驗(yàn)”二字，但是亂碼只看到了“網(wǎng)”字

   這部分源代碼（下載此課程的源代碼）：

2. package com.imooc.kaptcha;

3. 
   

4. import java.util.Random;

5. 
   

6. public class ChineseText extends Configurable implements TextProducer {

7. 
   

• public String getText() {

• int length = getConfig().getTextProducerCharLength();

• //char[] charS = getConfig().getTextProducerCharString();

• String[] s = new String[]{"慕","課","網(wǎng)","教","程","驗(yàn)","證","碼","實(shí)","例"};

• 
  

• Random rand = new Random();

• StringBuffer sb = new StringBuffer();

• for(int i = 0; i < length; i++){

• int ind = rand.nextInt(s.length);

• sb.append(s[ind]);

• }

• return sb.toString();

• }

1. /**

2. * 中文實(shí)例

3. * @return

4. */

5. public String getText1() {

6. int length = getConfig().getTextProducerCharLength();

7. String finalWord = "", firstWord = "";

8. int tempInt = 0;

9. String[] array = { "0", "1", "2", "3", "4", "5", "6", "7", "8", "9",

10. "a", "b", "c", "d", "e", "f" };

11. 
    

12. Random rand = new Random();

13. 
    

14. for (int i = 0; i < length; i++) {

15. switch (rand.nextInt(array.length)) {

16. case 1:

17. tempInt = rand.nextInt(26) + 65;

18. firstWord = String.valueOf((char) tempInt);

19. break;

20. case 2:

21. int r1,

22. r2,

23. r3,

24. r4;

25. String strH,

26. strL;// high&low

27. r1 = rand.nextInt(3) + 11; // 前閉后開[11,14)

28. if (r1 == 13) {

29. r2 = rand.nextInt(7);

30. } else {

31. r2 = rand.nextInt(16);

32. }

33. 
    

34. r3 = rand.nextInt(6) + 10;

35. if (r3 == 10) {

36. r4 = rand.nextInt(15) + 1;

37. } else if (r3 == 15) {

38. r4 = rand.nextInt(15);

39. } else {

40. r4 = rand.nextInt(16);

41. }

42. 
    

43. strH = array[r1] + array[r2];

44. strL = array[r3] + array[r4];

45. 
    

46. byte[] bytes = new byte[2];

47. bytes[0] = (byte) (Integer.parseInt(strH, 16));

48. bytes[1] = (byte) (Integer.parseInt(strL, 16));

49. 
    

50. firstWord = new String(bytes);

51. break;

52. default:

53. tempInt = rand.nextInt(10) + 48;

54. firstWord = String.valueOf((char) tempInt);

55. break;

56. }

57. finalWord += firstWord;

58. }

59. return finalWord;

60. }

61. }