求1+2+3.......+n的值且n大于零小于200,這樣做對嗎
#include<stdio.h>
int main()
{
?int N,a;
?a=0;
?a=a+N;
?while (N>0&&N<200);
?N++;
?printf("%d\n","1到N的和") ;
?return 0;
#include<stdio.h>
int main()
{
?int N,a;
?a=0;
?a=a+N;
?while (N>0&&N<200);
?N++;
?printf("%d\n","1到N的和") ;
?return 0;
2016-01-28
舉報(bào)
2016-01-28
#include<stdio.h>
int main()
{
int n,sum=0;
printf("請輸入一個(gè)1至200的數(shù):");
scanf("%d",&n);
if(n<1&&n>200)
printf("您輸入有誤.");
for(n;n>0;n--)
{
sum=sum+n;
}
printf("和為%d\n",sum);
return 0;
}
2016-01-28
#include<stdio.h>
int main()
{
?int N,a;
?while (N>0&&N<200)
{
a += N;
N++;
}
?printf("1到N的和為:%d\n",a) ;
?return 0;
2016-01-28
#include<stdio.h>
int main()
{
?int N,a;
?while (N>0&&N<200)
{
a +=
N++;
}
?printf("1到N的和為:%d\n",a) ;
?return 0;