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請問這里面是怎么計算

?????? int one = 10 ;
??????? int two = 20 ;
??????? int three = 0 ;

three+=one;

?System.out.println("thrree+= ==> "+three);

為什么得出的結(jié)果是40,不應(yīng)該是10嗎?

正在回答

3 回答

public?class?HelloWorld{
????public?static?void?main(String[]?args)?{
	????int?one?=?10?;
????????int?two?=?20?;
????????int?three?=?0?;
????????three=one+two;
????????System.out.println("three=one+two?==>?"+three);
????????three+=one;
????????System.out.println("three+=?==>?"+three);
????????three-=one;
????????System.out.println("three-+"+three);
????????three*=one;
????????System.out.println("three*="+three);
????????three/=one;
????????System.out.println("three/="+three);
????????three%=one;
????????System.out.println("three%="+three);

你好,three+=one; 這一句的意思是,three + one 賦值給 three,這里上面已經(jīng)運行過?three=one+two;?

所以到?three+=one; 這一步的時候 three 的值是 30;運行?three+=one; 后相當于 three = 30 + 10;

因此,得到的 three 的值是 40;望樓主采納!

0 回復(fù) 有任何疑惑可以回復(fù)我~
#1

死神少 提問者

非常感謝!
2015-12-28 回復(fù) 有任何疑惑可以回復(fù)我~
public?class?HelloWorld{
????public?static?void?main(String[]?args)?{
	????int?one?=?10?;
????????int?two?=?20?;
????????int?three?=?0?;
????????three=one+two;
????????System.out.println("three=one+two?==>?"+three);?//30
????????three+=one;
????????System.out.println("thrree+=?==>?"+three);??//40
????????three-=one;
????????System.out.println("three-+"+three);????//30
????????three*=one;
????????System.out.println("three*="+three);????//300
????????three/=one;
????????System.out.println("three/="+three);????//30
????????three%=one;
????????System.out.println("three%="+three);????//0


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