判斷年份是不是閏年的兩個(gè)規(guī)則:
1、能被被4整除但不能被100整除;
2、能被400整除;
滿(mǎn)足其中之一就是閏年。
1、能被被4整除但不能被100整除;
2、能被400整除;
滿(mǎn)足其中之一就是閏年。
2021-12-12
clude <stdio.h>
int main()
{
int number=200;
int year=2014;
do{
year++;
? //這里是不是應(yīng)該寫(xiě)點(diǎn)什么?
}while(number<1000)? //這里好像缺點(diǎn)什么
printf("到%d年招工規(guī)模突破1000人\n", year);
return 0;
}
int main()
{
int number=200;
int year=2014;
do{
year++;
? //這里是不是應(yīng)該寫(xiě)點(diǎn)什么?
}while(number<1000)? //這里好像缺點(diǎn)什么
printf("到%d年招工規(guī)模突破1000人\n", year);
return 0;
}
2021-12-11
這樣可以通過(guò)
#include <stdio.h>
extern void printLine()
{
printf("**************\n");
}
int main()
{
say();
return 0;
}
#include <stdio.h>
extern void printLine()
{
printf("**************\n");
}
int main()
{
say();
return 0;
}
2021-12-11
#include <stdio.h>
int main()
{
char c = 'a';
int n =c; //將c賦值給n
float f = n; //將c賦值給f
double d = f; //將c賦值給d
printf("%d\n",n);
printf("%f\n",f);
printf("%lf\n",d);
return 0;
}
int main()
{
char c = 'a';
int n =c; //將c賦值給n
float f = n; //將c賦值給f
double d = f; //將c賦值給d
printf("%d\n",n);
printf("%f\n",f);
printf("%lf\n",d);
return 0;
}
2021-12-06
#include <stdio.h>
int main(){
int age = 18;
float height = 1.85;
char unit = 'm';
printf("小明今年%d歲\n", ("%d",age));
printf("小明身高%f%c\n",("%f",height),("%c",unit));
printf("%s","小明現(xiàn)在在慕課網(wǎng)上學(xué)習(xí)IT技術(shù)");
return 0;
}
運(yùn)行成功
int main(){
int age = 18;
float height = 1.85;
char unit = 'm';
printf("小明今年%d歲\n", ("%d",age));
printf("小明身高%f%c\n",("%f",height),("%c",unit));
printf("%s","小明現(xiàn)在在慕課網(wǎng)上學(xué)習(xí)IT技術(shù)");
return 0;
}
運(yùn)行成功
2021-12-04
這樣子就可以通過(guò)了
#include <stdio.h>
int main()
{
printf("**************\n");
printf("I love imooc\n");
printf("good good study!\n");
printf("day day up!\n");
printf("**************\n");
return 0;
}
// extern
#include <stdio.h>
int main()
{
printf("**************\n");
printf("I love imooc\n");
printf("good good study!\n");
printf("day day up!\n");
printf("**************\n");
return 0;
}
// extern
2021-12-03
int sxh;
int g , s , b ;
for(sxh = 100 ; sxh < 1000; sxh++)
{
g = sxh%10;
s = sxh/10%10;
b = sxh/100;
if(g*g*g+s*s*s+b*b*b ==sxh)
{
printf("水仙話(huà)數(shù)學(xué):%d\n",sxh);
}
}
return 0;
}
int g , s , b ;
for(sxh = 100 ; sxh < 1000; sxh++)
{
g = sxh%10;
s = sxh/10%10;
b = sxh/100;
if(g*g*g+s*s*s+b*b*b ==sxh)
{
printf("水仙話(huà)數(shù)學(xué):%d\n",sxh);
}
}
return 0;
}
2021-11-26
#include <stdio.h>
int main()
{
選擇你們認(rèn)為最合理的循環(huán)結(jié)構(gòu)完成功能吧 */
int sum = 0; //定義計(jì)算結(jié)果變量sum
int i = 1; //定義循環(huán)數(shù)字變量i
int flag = 1; //定義符號(hào)狀態(tài)變量flag
//使用for循環(huán)
for(i=1;i<=100;i++)
{
sum=sum+(i%2-1)*i+(i%2)*i;
}
printf("sum=%d\n",sum);
return 0;
}
int main()
{
選擇你們認(rèn)為最合理的循環(huán)結(jié)構(gòu)完成功能吧 */
int sum = 0; //定義計(jì)算結(jié)果變量sum
int i = 1; //定義循環(huán)數(shù)字變量i
int flag = 1; //定義符號(hào)狀態(tài)變量flag
//使用for循環(huán)
for(i=1;i<=100;i++)
{
sum=sum+(i%2-1)*i+(i%2)*i;
}
printf("sum=%d\n",sum);
return 0;
}
2021-11-24
我的判斷條件應(yīng)該適用于所有矩陣對(duì)角線(xiàn),望采納{
if((i+j)%2==0)
sum+=arr[i][j];
}
if((i+j)%2==0)
sum+=arr[i][j];
}
2021-11-22