# Enter a code
def square_of_sum(mylist):
s = 0
for i in mylist:
s += i**2
return s
mylist = [1, 2, 3, 4, 5]
print(square_of_sum(mylist))
def square_of_sum(mylist):
s = 0
for i in mylist:
s += i**2
return s
mylist = [1, 2, 3, 4, 5]
print(square_of_sum(mylist))
2020-09-22
mylist = []
for i in range(1,101,1):
mylist.append(i*i)
print(sum(mylist))
for i in range(1,101,1):
mylist.append(i*i)
print(sum(mylist))
2020-09-22
已采納回答 / qq_棠梨煎雪故人來_03907185
你可以理解為調(diào)用函數(shù)，讓template這個對象調(diào)用format函數(shù)，大多數(shù)編程語言里"."都可以這么理解。
2020-09-22
s1 = set([1, 2, 3, 4, 5])
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
s = s2.isdisjoint(s1)
if s == False:
for i in s1:
if i in s2:
print(i)
s2 = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
s = s2.isdisjoint(s1)
if s == False:
for i in s1:
if i in s2:
print(i)
2020-09-22
s = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
num=0
while True:
if num>19
break
num=num+1
ss=s[0:num]
print(ss)
這個是哪里錯了.
num=0
while True:
if num>19
break
num=num+1
ss=s[0:num]
print(ss)
這個是哪里錯了.
2020-09-22
老師這個答案好像錯了哦！
我寫的是，供參考
num=1
sum=0
while num <= 9:
if num % 2==0:
sum = sum + num
num=num+1
continue
num=num+1
print(sum)
我寫的是，供參考
num=1
sum=0
while num <= 9:
if num % 2==0:
sum = sum + num
num=num+1
continue
num=num+1
print(sum)
2020-09-21
#浮點數(shù)
3.1415926
#字符串
'Learn Python in imooc.'
#整數(shù)
100
#二進制
0b1101
3.1415926
#字符串
'Learn Python in imooc.'
#整數(shù)
100
#二進制
0b1101
2020-09-21
T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1, 2, 3, 4, 5))
s = 0
for i in T:
if '(' in str(i):
s+=1
print(s)
s = 0
for i in T:
if '(' in str(i):
s+=1
print(s)
2020-09-20
最新回答 / 竄天吼猴
# Enter a codeT = ((1+2),? ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))num = 0for t in T:? ? if isinstance(t,tuple):? ? ? ? num += 1print(num)
2020-09-20
最新回答 / 超級辣的辣子雞
你這個在num<=6的時候就跳回了for循環(huán)了，不會執(zhí)行print函數(shù)了，當循環(huán)多次，你的num=6了，不再執(zhí)行continue，所以輸出100
2020-09-19