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<title>prototype与jQuery冲突解决4</title>
<!-- 引入 prototype -->
<script class="lazyload" src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAYAAAAfFcSJAAAAAXNSR0IArs4c6QAAAARnQU1BAACxjwv8YQUAAAAJcEhZcwAADsQAAA7EAZUrDhsAAAANSURBVBhXYzh8+PB/AAffA0nNPuCLAAAAAElFTkSuQmCC" data-original="/ajaxjs/prototype-1.6.0.3.js" type="text/javascript"></script>
<!-- 引入 jQuery -->
<script class="lazyload" src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAYAAAAfFcSJAAAAAXNSR0IArs4c6QAAAARnQU1BAACxjwv8YQUAAAAJcEhZcwAADsQAAA7EAZUrDhsAAAANSURBVBhXYzh8+PB/AAffA0nNPuCLAAAAAElFTkSuQmCC" data-original="/ajaxjs/jquery-1.3.1.js" type="text/javascript"></script>
</head>
<body>
<p id="pp">test---prototype</p>
<p >test---jQuery</p>
<script type="text/javascript">
jQuery.noConflict(); //将变量$的控制权让渡给prototype.js
(function($){ //定义匿名函数并设置形参为$
$(function(){ //匿名函数内部的$均为jQuery
$("p").click(function(){ //继续使用 $ 方法
alert($(this).text());
});
});
})(jQuery); //执行匿名函数且传递实参jQuery
$("pp").style.display = 'none';//使用prototype
</script>
</body>
</html>
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