问题: jquery中使用submit提交按钮时，当return false后，依然会提交表单.
解决: 使用button按钮，而不是submit按钮
<script type="text/javascript" class="lazyload" src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAYAAAAfFcSJAAAAAXNSR0IArs4c6QAAAARnQU1BAACxjwv8YQUAAAAJcEhZcwAADsQAAA7EAZUrDhsAAAANSURBVBhXYzh8+PB/AAffA0nNPuCLAAAAAElFTkSuQmCC" data-original="scripts/jquery-2.0.2.js"></script>
<script type="text/javascript">
function check(){
var npassword=$("#npassword").val();
var npassword2=$("#npassword2").val();
if(npassword==null||npassword==""){
alert("密码不能为空！");
$("#npassword").focus();
return false;
} else if(npassword2!=npassword){
alert("两次密码不一致");
$("#npassword2").attr("value","");
$("#npassword2").focus();
return false;
}else{
$("#form").submit();
}
}
</script>
</head>
<body bgcolor="#E2E4F0">
<form name="form" id="form" action="selfservice.jsp" method="post" >
<input type="hidden" name="action" value="modpassword"/>
<table border="2" align="center" >
<tr>
<td>新密码：</td>
<td><input type="password" id="npassword" name="npassword"/></td>
</tr>
<tr>
<td>确认密码：</td>
<td><input type="password" id="npassword2" name="npassword2"/></td>
</tr>
<tr>
<td><input type="button" value="提交" check();"></td>
<td><input type="reset" value="重置"></td>
</tr>
</table>
</form>
</body>
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